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Chemistry Regents January 2008 - Question 41 PDF Print E-mail
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Written by The Chemistry Wizard   

chemjan08q (41)

(1) 2.5 L is the correct answer.

If we plug in the values for Standard temperature (0C or 273K) and pressure (101.3 kPa or 1atm) into the ratio for gases, we can find the ratio for PV = nRT

You can ignore the factor ‘’R’’ as it is present in both equations.

(1atm) x (2L ) = n (273) ------ (1x2)/ 273 = .007 moles

(.88atm) x (zL) = .007 moles (303)

X = 2.5

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Last Updated on Wednesday, 04 March 2009 10:24
 

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