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Moles/Stoichiometry
NYS Chemistry Regents Review Practice - Moles/Stoichiometry - Question 01 Print E-mail
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Practice Questions
1. Given the unbalanced equation: Al + O2 = Al2O3 When this equation is completely balanced using the smallest whole numbers, what is the sum of the coefficients?

A)    7

B)    5

C)    9

D)    4

Correct Answer: Option C - 9

 

4Al + 3O2 = 2Al2O3.

Coefficients are the numbers in front of the element symbols. Add 4 + 3 + 2 to get 9.

Hence, options A, B and D are incorrect.

 
NYS Chemistry Regents Review Practice - Moles/Stoichiometry - Question 02 Print E-mail
Practice Questions
2. Which is the correct formula for nitrogen oxide?

A)    N2O

B)    NO

C)    N2O3

D)    NO2

Correct Answer: Option A - N2O

The oxidation number for Oxygen (O) is -2 and the oxidation number for Nitrogen (1) is +1. Since this is a compound, the oxidation numbers of the atoms in the compound must equal zero. In N2O, note how N (2)( +1) or a +2 charge will cancel out the -2 charge of one oxygen ion.

Hence, options B, C and D are incorrect.

 
NYS Chemistry Regents Review Practice - Moles/Stoichiometry - Question 03 Print E-mail
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Practice Questions
3. Given the balanced equation representing a reaction:

2CO(g) + O2(g) 2CO2(g)

What is the mole ratio of CO(g) to CO2(g) in this reaction?

A)    2:1

B)    1:1

C)    1:2

D)    3:2

Correct Answer: Option B - 1:1

A mole is the number of protons or neutrons needed to make up one gram.

1 mole = 6.02x1023

The ratio of the moles of one reactant or product to the moles of another reactant of product in the balanced equation for a chemical reaction is called a mole ratio.

2CO(g) 2CO2(g)

= 2 2

= 2: 2

= 1:1

Hence, the options A, C and D are incorrect.

 
NYS Chemistry Regents Review Practice - Moles/Stoichiometry - Question 04 Print E-mail
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Practice Questions
4. Given the equation: H2(g) + Cl2(g) 2HCl(g) What is the total number of moles of HCl(g) produced when 3 moles of H2(g) is completely consumed?

A)    5 moles

B)    3 moles

C)    6 moles

D)    2 moles

Correct Answer: Option C - 6 moles

From the above equation it is inferred that 1 unit of hydrogen can combine with 1 unit of chlorine to form 2 units of hydrochloric acid.

1 + 1 = 2

Hence, 3 moles of hydrogen can be completely consumed by 3 moles of chlorine to for 6 moles of hydrochloric acid.

3 + 3 = 6

Hence, options A, B and D are incorrect.

 
NYS Chemistry Regents Review Practice - Moles/Stoichiometry - Question 05 Print E-mail
Practice Questions
5. What is the gram formula mass of K2CO3?

A)    138 g

B)    99 g

C)    106 g

D)    67 g

Correct Answer: Option A - 138 g

The unified atomic mass unit (u), or dalton (Da) or, sometimes, universal mass unit, is a unit of mass used to express atomic and molecular masses. It is the approximate mass of a hydrogen atom, a proton, or a neutron.

The precise definition is that it is one twelfth of the mass of an isolated atom of carbon-12 (12C) at rest and in its ground state.

1 u = 1/NA gram = 1/ (1000 NA) kg   (where NA is Avogadro's number)

1 u = 1.660538782(83)×10-27 kg = 931.494028(23) MeV/c2

  • Atomic mass of K: 39.0983 amu
  • Atomic mass of C: 12.0107 amu
  • Atomic mass of O: 15.9994 amu

Hence from the above equation, we have the following calculation

K =39 x 2 = 78 g;

C =12 x 1 = 12 g;

O =16 x 3 = 48 g.

Total is 78 + 12 + 48 or 138 g.

Hence, options B, C and D are incorrect.

 
NYS Chemistry Regents Review Practice - Moles/Stoichiometry - Question 06 Print E-mail
Practice Questions
6. What is the total number of moles of hydrogen gas contained in 9.03 x 1023

A)    6.02 moles

B)    1.5 moles

C)    2.00 moles

D)    9.03 moles

Correct Answer: Option B - 1.5 moles

A mole is the number of protons or neutrons needed to make up one gram.

1 mole = 6.02x1023

Divide 9.03 x 1023 by 6.02 x 1023 to find the number of moles of hydrogen gas.

9.02 x 1023 / 6.02 x 1023 = 1.5 moles

Hence, options A, C and D are incorrect.

 
NYS Chemistry Regents Review Practice - Moles/Stoichiometry - Question 07 Print E-mail
Practice Questions
7. What is the mass in grams of 3.0 x 1023 molecules of CO2?

A)    44 g

B)    66 g

C)    22 g

D)    80 g

Correct Answer: Option C - 22 g

Atomic mass of carbon is 12 and atomic mass of oxygen is 16

Hence, the gram mass of CO2 = 12 + 2 (16) = 44

Thus, one mole of CO2 has a gram mass of 44 grams and contains 1 mole of molecules (6.02 x 1023).

You are given 3 x 1023 equals 1/2 the mass of 1 mole of CO2 or 1/2 x 44 = 22 g.

Hence, options A, B and D are incorrect.

 
NYS Chemistry Regents Review Practice - Moles/Stoichiometry - Question 08 Print E-mail
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Practice Questions
8. What is the molarity of a KF (aqueous) solution containing 116 grams of KF in 1.00 liter of solution?

A)    2.00 M

B)    1.00 M

C)    3.00 M

D)    5.00 M

Correct Answer: Option A - 2.00 M

Molar concentration (also called molarity, amount concentration or substance concentration) is a measure of the concentration of a solute in a solution, or of any molecular, ionic, or atomic species in a given volume

Firstly find the moles of solute using the formula: mass of solute (g) divided by formula mass of solute

Now divide the moles of solute by volume of solution in liters M / V. Or if you know the moles of solute,

Molarity = moles of solute divided by volume of solution in liters.

KF has a formula mass of 39 + 19 or 58 g/mole. Since 116 grams are given, 116g / 58g/mole = 2 moles of solute.

To find the Molarity, take 2 moles of solute and divide by 1 L of solution. 2 moles / 1 L = 2.00 M solution

Hence options B, C and D are incorrect.

 
NYS Chemistry Regents Review Practice - Moles/Stoichiometry - Question 09 Print E-mail
Practice Questions
9. At Standard temperature and pressure, 32.0 liters of O2 contain the same number of molecules as:

A)    44.8 L of He

B)    32. 0 L of H2

C)    28.0 L of N2

D)    22.4 L Ar

Correct Answer: Option B - 32. 0 L of H2

Avogadro's law (sometimes referred to as Avogadro's hypothesis or Avogadro's principle) is a gas law named after, Avagadro hypothesized that:

Equal volumes of ideal or perfect gases, at the same temperature and pressure, contain the same number of particles, or molecules. Thus, the number of molecules in a specific volume of gas is independent of the size or mass of the gas molecules.

As an example, equal volumes of molecular hydrogen and nitrogen would contain the same number of molecules, as long as they are at the same temperature and pressure and observe ideal or perfect gas behavior. In practice, for real gases, the law only holds approximately, but the agreement is close enough for the approximation to be useful.

Hence, options A, C and D are incorrect.

 
NYS Chemistry Regents Review Practice - Moles/Stoichiometry - Question 10 Print E-mail
Practice Questions
10. Which of the following is a binary compound?

A)    Hydrogen sulfate

B)    Ammonium sulfide

C)    Ammonium sulfate

D)    Hydrogen sulfide

Correct Answer: Option D - Hydrogen sulfide

A binary compound is a chemical compound that contains exactly two different elements.

Hydrogen sulfide (or hydrogen sulphide) is the chemical compound with the formula H2S. This colorless, toxic and flammable gas is partially responsible for the foul odor of rotten eggs and flatulence.

Incorrect Options

Hydrogen sulfate has 3 kinds of atoms (H, S, O). Its also referred as sulphuric acid. Sulfuric (or sulphuric) acid, H2SO4, is a strong mineral acid.

Ammonium sulphide has 3 kinds (N, H, S). Ammonium sulfide, also known as diammonium sulfide, is an unstable salt with the formula (NH4)2S

Ammonium sulfate has 4 kinds (N, H, S, O). Ammonium sulfate (NH4)2SO4, is an inorganic salt

 
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